PARAMETRIC EQUATIONS OF CONICS
The conic sections can be represented by parametric equations. This page shows how one derives the parametric equations of the conic sections.
The Circle and Ellipse
The equation of an ellipse centered at (h, k) in standard form is: \(\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1\). To express in parametric form, begin by solving for y – k:
(i) \(y-k = \frac{b}{a}\sqrt{a^2-(x-h)^2}\)
Now, let \(x - h = a\cos\theta\). Then,
(ii) \(y-k = \frac{b}{a}\sqrt{a^2 - a^2\cos^{2}\theta} = b\sin\theta\)
Therefore,
\[x = a\cos\theta + h\]
\[y = b\cos\theta + k\]
If a = b = r, the parametric equation reduces to an equation of a circle of radius r.
The Hyperbola
The equation of a hyperbola centered at (h, k) in standard form is: \(\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1\) or \(-\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1\). To express in parametric form, begin by solving for x – h in the first equation:
(i) \(x-h = \frac{a}{b}\sqrt{b^2+(y-k)^2}\)
Now, let \(y - k = b\tan\theta\). Then,
(ii) \(x-h = \frac{a}{b}\sqrt{b^2 + b^2\tan^{2}\theta} = a\sec\theta\)
Therefore,
\[x = a\sec\theta + h\]
\[y = b\tan\theta + k\]
If the hyperbola is defined by the equation \(-\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1\), the equation of the hyperbola with a vertical transverse axis parallel to the y-axis in parametric form is:
\[x = a\tan\theta + h\]
\[y = b\sec\theta + k\]